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6. Mr. Kasam runs a small business of making earthen pots. He makes certain number of pots on daily basis. Production cost of each pot is ₹40 more than 10 times total number of pots, he makes in one day. If production cost of all pots per day is ₹600, find production cost of one pot and number of pots he makes   per day.

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Sol.    Let the number of pots Mr. Kasam makes per day be \(x\).
          Production cost of all pots = ₹600.00

∴        Production cost of per pot =  \(₹{600\over x}\)

          According to the given condition,

∴                                          10\(x\)   +   40   =   \(600\over x\)

∴                               10(\(x^2\) + 4\(x\) – 60)      =   0                                           [Multiplying throughout by \(x\)]

∴                                       \(x^2\)  +  4\(x\) – 60   =  \(0\over 10\) 

∴                                 \(x^2\) + 10\(x\) – 6\(x\) – 60 =   0

∴                             \(x\)(\(x\) + 10) – 6(\(x\) + 10) =    0
∴                                       (\(x\) + 10) (\(x\) – 6) =    0
∴            \(x\)  +  10   =   0     or    \(x\)  –  6     =   0
∴                     \(x\)    = –10   or            \(x\)     =   6
      \(x\) = –10 is not acceptable because number of pots can not be negative.
       Number of pots Mr. Kasam makes = 6

       Production cost of per pot   =  \(₹{600\over 6}\)  =  ₹100

  

uÉaÉïxÉqÉÏMüUhÉ August 10 , 2018 0 Comments 11 views